Two pure inductors each of self inductance L | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When inductors are connected in parallel and are well separated (meaning there is no mutual induction between them),they follow the same rules as

Vedclass · Accepted Answer

$\frac{L}{2}$

Vedclass · Answer

(C) When inductors are connected in parallel and are well separated (meaning there is no mutual induction between them),they follow the same rules as resistors in parallel.For two inductors $L_1$ and $L_2$ in parallel,the equivalent inductance $L_{eq}$ is given by the formula:$\frac{1}{L_{eq}} = \frac{1}{L_1} + \frac{1}{L_2}$Given $L_1 = L$ and $L_2 = L$,we have:$\frac{1}{L_{eq}} = \frac{1}{L} + \frac{1}{L} = \frac{2}{L}$Therefore,$L_{eq} = \frac{L}{2}$.

Two pure inductors each of self inductance $L$ are connected in parallel but are well separated from each other. The total inductance is

Similar Questions

The equivalent inductance of two inductances is $2.4 \, H$ when connected in parallel and $10 \, H$ when connected in series. The difference between the two inductances is .......... $H$.

The equivalent inductance between $A$ and $B$ is equal to

Two inductors $L_1$ and $L_2$ are connected in parallel,and a time-varying current flows as shown. The ratio of currents $i_1/i_2$ at any time $t$ is:

Two identical induction coils,each of inductance $L$,are joined in series and placed very close to each other such that the winding direction of one is exactly opposite to that of the other. What is the net inductance?

$A$ circuit contains two inductors of self-inductance $L_1$ and $L_2$ connected in series as shown in the figure. If $M$ is the mutual inductance between them,then the effective inductance of the circuit will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module