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(B) The orbital speed of a satellite at a distance $r$ from the center of a planet is given by $v = \sqrt{\frac{GM}{r}}$.Since $v \propto \frac{1}{\sq

Vedclass · Accepted Answer

$6$

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(B) The orbital speed of a satellite at a distance $r$ from the center of a planet is given by $v = \sqrt{\frac{GM}{r}}$.Since $v \propto \frac{1}{\sqrt{r}}$,we can write the ratio of the speeds of satellites $A$ and $B$ as:$\frac{v_A}{v_B} = \sqrt{\frac{r_B}{r_A}}$Given $r_A = 4R$ and $r_B = R$,we have:$\frac{v_A}{v_B} = \sqrt{\frac{R}{4R}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$Given the speed of satellite $A$ is $v_A = 3V$,we substitute this into the ratio:$\frac{3V}{v_B} = \frac{1}{2}$Therefore,$v_B = 3V 	imes 2 = 6V$.

Two satellites $A$ and $B$ go round a planet $P$ in circular orbits having radii $4R$ and $R$ respectively. If the speed of the satellite $A$ is $3V$,the speed of the satellite $B$ will be ........ $V$.

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