Two satellites $A$ and $B$ move around the Earth in the same orbit. The mass of $A$ is twice the mass of $B$. The quantity which is the same for the two satellites will be:

$A$ satellite of the earth is revolving in a circular orbit with a uniform velocity $V$. If the gravitational force suddenly disappears,the satellite will

$A$ satellite of mass $M$ is revolving in a circular orbit of radius $r$ around the Earth. The time period of revolution of the satellite is:

$A$ satellite can be in a geostationary orbit around a planet at a distance $r$ from the centre of the planet. If the angular velocity of the planet about its axis doubles,a satellite can now be in a geostationary orbit around the planet if its distance from the centre of the planet is

$A$ double star is a system of two stars rotating about their centre of mass only under their mutual gravitational attraction. Let the stars have masses $m$ and $2m$ and their separation be $l$. Their time period of rotation about their centre of mass will be proportional to:

$A$ satellite of mass $M$ is in a circular orbit of radius $R$ about the center of the Earth. $A$ meteorite of the same mass $M$,falling towards the Earth,collides with the satellite completely inelastically. The speeds of the satellite and the meteorite are the same,just before the collision. The subsequent motion of the combined body will be: