Two sitar strings A and B playing the note 'G | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The frequency of string $A$ is $f_A = 324 \ Hz$.Let the frequency of string $B$ be $f_B$.The beat frequency is given by $n = |f_A - f_B| = 6 \ Hz$

Vedclass · Accepted Answer

$318$

Vedclass · Answer

(D) The frequency of string $A$ is $f_A = 324 \ Hz$.Let the frequency of string $B$ be $f_B$.The beat frequency is given by $n = |f_A - f_B| = 6 \ Hz$.This implies $f_B = 324 \pm 6$,so $f_B = 330 \ Hz$ or $318 \ Hz$.The frequency of a string is given by $f = \frac{1}{2L} \sqrt{\frac{T}{\mu}}$,which means $f \propto \sqrt{T}$.When the tension $T$ in string $A$ is reduced,its frequency $f_A$ decreases.If $f_B = 330 \ Hz$,then initially $f_B - f_A = 330 - 324 = 6 \ Hz$. As $f_A$ decreases,the difference $(f_B - f_A)$ increases,so the beat frequency would increase.If $f_B = 318 \ Hz$,then initially $f_A - f_B = 324 - 318 = 6 \ Hz$. As $f_A$ decreases,the difference $(f_A - f_B)$ decreases. Since the beat frequency reduced to $3 \ Hz$,this matches the condition.Therefore,the frequency of $B$ is $318 \ Hz$.

Similar Questions

$A$ tuning fork $A$ of frequency $200 \ Hz$ is sounded with fork $B,$ the number of beats per second is $5.$ By putting some wax on $A,$ the number of beats increases to $8.$ The frequency of fork $B$ is .... $Hz$

$A$ tuning fork $A$ of frequency $250 \,Hz$ and another tuning fork $B$ of frequency $x$ produce $5$ beats per second when vibrated together. If the fork $B$ is waxed and vibrated together with $A$, then $3$ beats per second are produced. Then $x=$ (in $\,Hz$)

Two strings $A$ and $B$ produce beats of frequency $\Delta f_1 > 0$. The tension in string $A$ is slightly increased and the beat frequency is found to be $\Delta f_2 > 0$. If the original frequency of $A$ is $f_0$ and $\Delta f_2 < \Delta f_1$, then the frequency of $B$ is

The displacement equations of sound waves produced by two sources are given by $y_1 = 5 \sin(400 \pi t)$ and $y_2 = 8 \sin(408 \pi t)$, where $t$ is time in seconds. If the waves are produced simultaneously, the number of beats produced per minute is

$A$ wave has simple harmonic motion whose period is $4\; s$,while another wave which also possesses simple harmonic motion has its period $3\; s$. If both are combined,then the resultant wave will have the period equal to ....... $s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module