Two solutions $A$ and $B$ are separated by a semi-permeable membrane. If liquid flows from $A$ to $B$,then:

$20 \text{ g}$ hemoglobin in a $1 \text{ L}$ aqueous solution $(A)$ at $300 \text{ K}$ is separated from pure water by a semi-permeable membrane. At equilibrium, the height of the solution in a tube dipped in solution $(A)$ is found to be $80.0 \text{ mm}$ higher than the tube dipped in water. The molar mass of hemoglobin is . . . . . . $\text{kg mol}^{-1}$. (Nearest integer) (Given: $g = 10 \text{ m s}^{-2}$, $R = 8.3 \text{ kPa dm}^3 \text{ K}^{-1} \text{mol}^{-1}$, density of solution = $1000 \text{ kg m}^{-3}$)

$A$ $5\%(w/v)$ solution of sucrose is isotonic with a $1\%(w/v)$ solution of substance '$A$'. What is the molar mass of substance '$A$'?

Arrange the following equimolar solutions according to increasing order of osmotic pressure [Assume complete ionisation]:
$A$. $KCl$
$B$. $BaCl_2$
$C$. $AlCl_3$
$D$. $Al_2(SO_4)_3$

$18 \ g$ glucose (Molar mass $= 180 \ g/mol$) is dissolved in $100 \ mL$ of water at $300 \ K$. If $R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$,what is the osmotic pressure of the solution (in $atm$)?

. . . . . . solution is hypertonic with reference to fluid inside the blood cell.