Two spheres A and B of radii 4 text{ cm} and | vedclass

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(B) Initial charges are $Q_1 = 80 \mu	ext{C}$ and $Q_2 = 40 \mu	ext{C}$.Radii are $r_1 = 4 	ext{ cm}$ and $r_2 = 6 	ext{ cm}$.When connected by a

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$32 \mu	ext{C}$ from $A$ to $B$

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(B) Initial charges are $Q_1 = 80 \mu	ext{C}$ and $Q_2 = 40 \mu	ext{C}$.Radii are $r_1 = 4 	ext{ cm}$ and $r_2 = 6 	ext{ cm}$.When connected by a wire,charge flows until both spheres reach the same potential.The new charge $Q_1^{\prime}$ on sphere $A$ is given by:$Q_1^{\prime} = \left( \frac{r_1}{r_1 + r_2} ight) (Q_1 + Q_2) = \left( \frac{4}{4 + 6} ight) (80 + 40) = \left( \frac{4}{10} ight) (120) = 48 \mu	ext{C}$.The charge that flows from sphere $A$ to sphere $B$ is:$\Delta Q = Q_1 - Q_1^{\prime} = 80 \mu	ext{C} - 48 \mu	ext{C} = 32 \mu	ext{C}$.Since the result is positive,the charge flows from $A$ to $B$.

Two spheres $A$ and $B$ of radii $4 \text{ cm}$ and $6 \text{ cm}$ are given charges of $80 \mu\text{C}$ and $40 \mu\text{C}$ respectively. If they are connected by a fine wire,the amount of charge flowing from one to the other is

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