Two springs of force constants $300 \, N/m$ (Spring $A$) and $400 \, N/m$ (Spring $B$) are joined together in series. The combination is compressed by $8.75 \, cm$. The ratio of energy stored in $A$ and $B$ is $\frac{E_A}{E_B}$. Then $\frac{E_A}{E_B}$ is equal to

  • A
    $\frac{4}{3}$
  • B
    $\frac{16}{9}$
  • C
    $\frac{3}{4}$
  • D
    $\frac{9}{16}$

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