Two straight lines $3x + 4y = 5$ and $4x - 3y = 15$ intersect at the point $A$. The equations of the lines passing through $(1, 2)$ and intersecting the given lines at $B$ and $C$ such that $AB = AC$ are

  • A
    $x + 4y = 9, 4x - y = 2$
  • B
    $9x - 2y = 5, 2x + 9y = 20$
  • C
    $6x - y = 4, x + 6y = 13$
  • D
    $7x + y = 9, x - 7y + 13 = 0$

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