(C) The beat frequency is given by $|n_A - n_B| = 4 \ Hz$.When the tension in string $A$ is increased,its frequency $n_A$ increases because $n \propto

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(C) The beat frequency is given by $|n_A - n_B| = 4 \ Hz$.When the tension in string $A$ is increased,its frequency $n_A$ increases because $n \propto \sqrt{T}$.Since the number of beats increases from $4$ to $7$ upon increasing $n_A$,it implies that $n_A$ must be greater than $n_B$ (i.e.,$n_A - n_B = 4$).If $n_A$ were less than $n_B$,increasing $n_A$ would decrease the beat frequency towards zero before increasing it again,but the problem implies a direct increase.Therefore,$n_A = n_B + 4$.Given $n_B = 480 \ Hz$,we have $n_A = 480 + 4 = 484 \ Hz$.

Class 11 Physics Waves Beats and Tuning fork

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Two stretched strings $A$ and $B$ when vibrated together produce $4$ beats per second. If the tension applied to the string $A$ is increased,the number of beats produced per second increases to $7$. If the frequency of string $B$ is $480 \ Hz$ initially,what is the frequency of string $A$ (in $Hz$)?

AP EAMCET 2024 All AP EAMCET

A
$473$
B
$476$
C
$484$
D
$487$

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Waves

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Beats and Tuning fork

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$A$ tuning fork $A$ produces $4$ beats/sec with another tuning fork $B$ of frequency $320 \text{ Hz}$. On filing the fork $A$,$4$ beats/sec are again heard. The frequency of fork $A$ after filing is .... $\text{Hz}$

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