Two strings X and Y of a sitar produce a beat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Frequency of string $X$ $(n_X)$ = $300 \ Hz$. Initial beat frequency = $|n_X - n_Y| = 4 \ Hz$. This implies the initial frequency of $Y$ $(

Vedclass · Accepted Answer

$296$

Vedclass · Answer

(A) Given: Frequency of string $X$ $(n_X)$ = $300 \ Hz$. Initial beat frequency = $|n_X - n_Y| = 4 \ Hz$. This implies the initial frequency of $Y$ $(n_Y)$ is either $300 - 4 = 296 \ Hz$ or $300 + 4 = 304 \ Hz$. When the tension of string $Y$ is increased,its frequency $n_Y$ increases because $n \propto \sqrt{T}$. Case $1$: If $n_Y = 296 \ Hz$,increasing the tension makes $n_Y$ approach $300 \ Hz$ (e.g.,$298 \ Hz$),so the beat frequency $|300 - 298| = 2 \ Hz$. This matches the given condition. Case $2$: If $n_Y = 304 \ Hz$,increasing the tension makes $n_Y$ move further away from $300 \ Hz$ (e.g.,$306 \ Hz$),so the beat frequency $|300 - 306| = 6 \ Hz$. This does not match the condition. Therefore,the original frequency of $Y$ was $296 \ Hz$.

Two strings $X$ and $Y$ of a sitar produce a beat frequency of $4 \ Hz$. When the tension of the string $Y$ is slightly increased,the beat frequency is found to be $2 \ Hz$. If the frequency of $X$ is $300 \ Hz$,then the original frequency of $Y$ was .... $Hz$.

Similar Questions

The frequency of a tuning fork is $n \ Hz$ and the velocity of sound in air is $V \ m/s$. When the tuning fork completes $x$ vibrations,the distance traveled by the wave is:

The frequencies of two sound sources are $256 \text{ Hz}$ and $260 \text{ Hz}$. At $t = 0$,the intensity of sound is maximum. Then the phase difference at the time $t = \frac{1}{16} \text{ s}$ will be

$A$ tuning fork of frequency $400 \ Hz$ is in unison with a sonometer wire. The number of beats heard per second,when the tension in the wire is increased by $1 \%$,will be

$A$ tuning fork of frequency $280\, Hz$ produces $10$ beats per second when sounded with a vibrating sonometer string. When the tension in the string increases slightly,it produces $11$ beats per second. The original frequency of the vibrating sonometer string is ... $Hz$.

Two waves $y_1 = 0.35 \sin(316 t)$ and $y_2 = 0.35 \sin(310 t)$ are propagating along the same direction. The number of beats produced per second is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module