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(C) For any temperature scale,the ratio of the difference between the reading and the melting point (ice point) to the difference between the boiling

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) For any temperature scale,the ratio of the difference between the reading and the melting point (ice point) to the difference between the boiling point (steam point) and the melting point is constant.$\frac{	ext{Reading}_X - MP_X}{BP_X - MP_X} = \frac{	ext{Reading}_Y - MP_Y}{BP_Y - MP_Y}$Given for thermometer $X$: $MP_X = 15^{\circ}$,$BP_X = 75^{\circ}$,Reading $= 60^{\circ}$.Given for thermometer $Y$: $MP_Y = 25^{\circ}$,$BP_Y = 125^{\circ}$.Substituting the values:$\frac{60 - 15}{75 - 15} = \frac{y - 25}{125 - 25}$$\frac{45}{60} = \frac{y - 25}{100}$$\frac{3}{4} = \frac{y - 25}{100}$$y - 25 = 75$$y = 100^{\circ}$

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