Two thick wires and two thin wires,all of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In configurations $P$ and $R$,the current entering the square divides into two parallel paths. Because the wires in each path have the same total

Vedclass · Accepted Answer

$P$ and $R$ only

Vedclass · Answer

(D) In configurations $P$ and $R$,the current entering the square divides into two parallel paths. Because the wires in each path have the same total resistance (each path consists of one thick and one thin wire),the current splits equally in both branches.Since the segments are symmetric with respect to the centre and carry equal currents in opposite directions relative to the centre,the magnetic field produced by each segment at the centre cancels out.Therefore,the net magnetic field at the centre is zero for cases $P$ and $R$.

Two thick wires and two thin wires,all of the same material and same length,form a square in three different ways $P$,$Q$,and $R$ as shown in the figure. With the current connection shown,the magnetic field at the centre of the square is zero in which cases?

Similar Questions

Charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively,which are at a distance $2L$ apart. $C$ is the midpoint between $A$ and $B$. The work done in moving a charge $+Q$ along the semicircle $CRD$ is:

The position of a projectile launched from the origin at $t=0$ is given by $\vec{r}=(40 \hat{i}+50 \hat{j}) \text{ m}$ at $t=2 \text{ s}$. If the projectile was launched at an angle $\theta$ from the horizontal,then $\theta$ is (take $g = 10 \text{ m/s}^2$)

Phenol can be converted into salicylic acid by heating with

Which of the following is a fossil pteridophyte?

Rate constant varies with temperature by the equation $\log _{10} k =5-\frac{2000}{T}$. We can conclude that $\left( R =8.314\ J\ mol ^{-1} K^{-1}\right) :-$

Vedclass Test Series

Exam Paper Generator

Online Exam Module