(C) The force per unit length between two parallel wires carrying currents $i_1$ and $i_2$ separated by a distance $d$ is given by the formula: $\frac

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Attract each other with a force of $\frac{\mu_0 i^2}{2\pi d}$

(C) The force per unit length between two parallel wires carrying currents $i_1$ and $i_2$ separated by a distance $d$ is given by the formula: $\frac{F}{l} = \frac{\mu_0 i_1 i_2}{2\pi d}$.Since both wires carry the same current $i$ in the same direction,$i_1 = i_2 = i$.Substituting these values,we get: $\frac{F}{l} = \frac{\mu_0 i^2}{2\pi d}$.According to the right-hand rule,parallel currents in the same direction exert an attractive force on each other.Therefore,the wires will attract each other with a force of $\frac{\mu_0 i^2}{2\pi d}$ per unit length.

Class 12 Physics Moving Charges and Magnetism Force on a Current Carrying Conductor

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Two thin,long,parallel wires,separated by a distance $d$,carry a current of $i$ in the same direction. They will

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A
Attract each other with a force of $\frac{\mu_0 i^2}{2\pi d^2}$
B
Repel each other with a force of $\frac{\mu_0 i^2}{2\pi d^2}$
C
Attract each other with a force of $\frac{\mu_0 i^2}{2\pi d}$
D
Repel each other with a force of $\frac{\mu_0 i^2}{2\pi d}$

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Moving Charges and Magnetism

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Force on a Current Carrying Conductor

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$A$ square loop of length $L$ is placed with its edges parallel to the $XY$-axes. The loop carries a current $I$. If the magnetic field in the region varies as $B = B_0 \left(1 + \frac{xy}{L^2}\right) \hat{k}$, then the magnitude of the net force on the loop will be:

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An arbitrarily shaped closed coil is made of a wire of length $L$ and a current $I$ ampere is flowing in it. If the plane of the coil is perpendicular to a uniform magnetic field $\vec{B}$, the net magnetic force on the coil is

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$A$ semicircular ring of radius $R$ carrying current $i$ is placed in a uniform magnetic field of intensity $B$ such that the plane of the wire is perpendicular to the magnetic field,as shown in the figure. The net force acting on the ring is

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Through two parallel wires $A$ and $B$,$10 \, A$ and $2 \, A$ of currents are passed respectively in opposite directions. If the wire $A$ is infinitely long and the length of the wire $B$ is $2 \, m$,the force on the conductor $B$,which is situated at a $10 \, cm$ distance from $A$,will be:

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$A$ wire carrying a current $I$ is placed inside a uniform magnetic field $\vec{B} = -B_0 \hat{k}$. The shape of the wire is parabolic and has the equation $y = 2x - x^2$. The force on the wire will be:

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Two thin,long,parallel wires,separated by a distance $d$,carry a current of $i$ in the same direction. They will

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$A$ square loop of length $L$ is placed with its edges parallel to the $XY$-axes. The loop carries a current $I$. If the magnetic field in the region varies as $B = B_0 \left(1 + \frac{xy}{L^2}\right) \hat{k}$, then the magnitude of the net force on the loop will be:

An arbitrarily shaped closed coil is made of a wire of length $L$ and a current $I$ ampere is flowing in it. If the plane of the coil is perpendicular to a uniform magnetic field $\vec{B}$, the net magnetic force on the coil is

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Through two parallel wires $A$ and $B$,$10 \, A$ and $2 \, A$ of currents are passed respectively in opposite directions. If the wire $A$ is infinitely long and the length of the wire $B$ is $2 \, m$,the force on the conductor $B$,which is situated at a $10 \, cm$ distance from $A$,will be:

$A$ wire carrying a current $I$ is placed inside a uniform magnetic field $\vec{B} = -B_0 \hat{k}$. The shape of the wire is parabolic and has the equation $y = 2x - x^2$. The force on the wire will be:

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