Two trains 140 ; m and 160 ; m long run at a | vedclass

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(D) Relative speed of the trains moving in opposite directions is the sum of their individual speeds: $v_r = 60 + 40 = 100 \; km/hr$.To convert the sp

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$10.8$

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(D) Relative speed of the trains moving in opposite directions is the sum of their individual speeds: $v_r = 60 + 40 = 100 \; km/hr$.To convert the speed into $m/s$,multiply by $\frac{5}{18}$: $v_r = 100 	imes \frac{5}{18} = \frac{500}{18} = \frac{250}{9} \; m/s$.The total distance to be covered to cross each other is the sum of the lengths of the two trains: $L = 140 + 160 = 300 \; m$.The time taken to cross each other is given by $t = \frac{L}{v_r}$.Substituting the values: $t = \frac{300}{250/9} = \frac{300 	imes 9}{250} = \frac{6 	imes 9}{5} = \frac{54}{5} = 10.8 \; seconds$.

Two trains $140 \; m$ and $160 \; m$ long run at a speed of $60 \; km/hr$ and $40 \; km/hr$ respectively in opposite directions on parallel tracks. The time (in $seconds$) which they take to cross each other is:

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