Two trains are running at 40 ; km/hr and 20 ; | vedclass

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(D) The relative speed of the faster train with respect to the slower train is calculated as the difference between their speeds because they are movi

Vedclass · Accepted Answer

$27 \frac{7}{9}$

Vedclass · Answer

(D) The relative speed of the faster train with respect to the slower train is calculated as the difference between their speeds because they are moving in the same direction.Relative speed $= 40 \; km/hr - 20 \; km/hr = 20 \; km/hr$.To convert the speed from $km/hr$ to $m/s$,we multiply by $\frac{5}{18}$.Relative speed $= 20 	imes \frac{5}{18} = \frac{100}{18} = \frac{50}{9} \; m/s$.Let the length of the faster train be $x \; meters$.Since the train passes a man in the slower train,the distance covered is equal to the length of the faster train $(x)$.Using the formula $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$:$x = \frac{50}{9} \; m/s 	imes 5 \; s = \frac{250}{9} \; m$.Converting the improper fraction to a mixed fraction: $\frac{250}{9} = 27 \frac{7}{9} \; m$.

Two trains are running at $40 \; km/hr$ and $20 \; km/hr$ respectively in the same direction. The faster train completely passes a man in the slower train in $5 \; seconds$. What is the length (in $m$) of the faster train?

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