Two trains running at the rate of 45 ; km/h a | vedclass

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(C) Let the lengths of the two trains be $L_1$ and $L_2$ in meters.Relative speed in opposite direction $= 45 + 36 = 81 \; km/h$.Convert to $m/s$: $81

Vedclass · Accepted Answer

$75, 105$

Vedclass · Answer

(C) Let the lengths of the two trains be $L_1$ and $L_2$ in meters.Relative speed in opposite direction $= 45 + 36 = 81 \; km/h$.Convert to $m/s$: $81 	imes \frac{5}{18} = 22.5 \; m/s$.Since they pass each other in $8 \; seconds$,the sum of their lengths is $L_1 + L_2 = 22.5 	imes 8 = 180 \; m$.Relative speed in the same direction $= 45 - 36 = 9 \; km/h$.Convert to $m/s$: $9 	imes \frac{5}{18} = 2.5 \; m/s$.$A$ person in the faster train observes the other train passing in $30 \; seconds$. This means the length of the slower train $(L_2)$ is covered at the relative speed: $L_2 = 2.5 	imes 30 = 75 \; m$.Therefore,the length of the faster train is $L_1 = 180 - 75 = 105 \; m$.The lengths are $105 \; m$ and $75 \; m$.

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