Two trains running in opposite directions cross a man standing on the platform in $27 \;seconds$ and $17 \;seconds$ respectively, and they cross each other in $23 \;seconds$. The ratio of their speeds is

Two trains are running in opposite directions with the same speed. If the length of each train is $120 \; m$,and they cross each other in $12 \; s$,then the speed of each train is (in $km/h$):

$A$ jogger running at $9 \; km/hr$ alongside a railway track is $240 \; m$ ahead of the engine of a $120 \; m$ long train running at $45 \; km/hr$ in the same direction. In how much time (in $sec$) will the train pass the jogger?

Length of a train and that of a platform are equal. If with a speed of $135 \; km/hr$,the train crosses the platform in $40 \; seconds$,then the length (in $m$) of the train is:

$A$ train covers a distance between two stations $A$ and $B$ in $45$ minutes. If the speed is reduced by $5 \; km/h$,it will cover the same distance in $48$ minutes. What is the distance between the two stations $A$ and $B$ (in $km$)? Also,find the speed of the train.

How many seconds will a $500 \;m$ long train take to cross a man walking with a speed of $3 \;km/h$ in the same direction as the moving train,if the speed of the train is $63 \;km/h$?