(D) Let the time taken for the trains to meet be $t$ hours.Distance travelled by the first train $D_1 = 50t$.Distance travelled by the second train $D

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(D) Let the time taken for the trains to meet be $t$ hours.Distance travelled by the first train $D_1 = 50t$.Distance travelled by the second train $D_2 = 40t$.According to the problem,the first train travelled $100\, km$ more than the second:$D_1 - D_2 = 100$$50t - 40t = 100$$10t = 100$$t = 10\, \text{hours}$.The total distance between $P$ and $Q$ is the sum of the distances covered by both trains:$\text{Total Distance} = D_1 + D_2 = 50t + 40t = 90t$.Substituting $t = 10$:$\text{Total Distance} = 90 \times 10 = 900\, km$.

Competitive Quantitative Aptitude Time and Distances Time and Distances

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Two trains start from $P$ and $Q$ respectively and travel towards each other at a speed of $50\, km/hr$ and $40\, km/hr$ respectively. By the time they meet,the first train has travelled $100\, km$ more than the second. The distance between $P$ and $Q$ is (in $km$):

A
$500$
B
$630$
C
$660$
D
$900$

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If the length of the train is $700 \, m$ and the length of the platform is $500 \, m$,find the time taken by the train moving at $54 \, km/h$ to cross the platform (in $sec$).

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Two trains start from $P$ and $Q$ respectively and travel towards each other at a speed of $50\, km/hr$ and $40\, km/hr$ respectively. By the time they meet,the first train has travelled $100\, km$ more than the second. The distance between $P$ and $Q$ is (in $km$):

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If the length of the train is $700 \, m$ and the length of the platform is $500 \, m$,find the time taken by the train moving at $54 \, km/h$ to cross the platform (in $sec$).

$A$ car starts from $A$ for $B$ travelling at $20 \, km/h$. $1 \frac{1}{2} \, hours$ later,another car starts from $A$ and,travelling at the rate of $30 \, km/h$,reaches $B$ $2 \frac{1}{2} \, hours$ before the first car. Find the distance from $A$ to $B$ (in $km$).

What is the speed of the train in $km/h$?Statements:$I.$ The train crosses an $x$ meter-long platform in $n$ seconds.$II.$ The length of the train is $y$ meters.$III.$ The train crosses a signal pole in $m$ seconds.

$A$ truck covers a distance of $396 \, km$ in $5 \, hours \, 30 \, minutes$. The average speed of a bike is $\frac{4}{3}$ of the average speed of the truck. What is the time taken by the bike to cover a distance of $12 \, km$ less than the distance covered by the truck?

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What is the speed of the train in $km/h$?
Statements:
$I.$ The train crosses an $x$ meter-long platform in $n$ seconds.
$II.$ The length of the train is $y$ meters.
$III.$ The train crosses a signal pole in $m$ seconds.