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(A) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4\pi \varepsilon_0} \frac{Q}{r}$.Let the two char

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(A) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4\pi \varepsilon_0} \frac{Q}{r}$.Let the two charges be $+q$ and $-q$,separated by a distance $2d$. The midpoint $O$ is at a distance $d$ from both charges.The potential at the midpoint $O$ is the algebraic sum of the potentials due to both charges:$V_O = V_{+q} + V_{-q}$$V_O = \frac{1}{4\pi \varepsilon_0} \frac{q}{d} + \frac{1}{4\pi \varepsilon_0} \frac{(-q)}{d}$$V_O = \frac{1}{4\pi \varepsilon_0} \left( \frac{q}{d} - \frac{q}{d} \right) = 0$Therefore,the potential at the midpoint is zero.

Two unlike charges of magnitude $q$ are separated by a distance $2d$. The potential at a point midway between them is

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