Two very long,straight,parallel conductors A | vedclass

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(C) The formula for the force per unit length between two parallel current-carrying conductors is given by:$\frac{F}{\ell} = \frac{\mu_0 i_1 i_2}{2 \p

Vedclass · Accepted Answer

$1 	imes 10^{-4} 	ext{ N/m}$ and is attractive

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(C) The formula for the force per unit length between two parallel current-carrying conductors is given by:$\frac{F}{\ell} = \frac{\mu_0 i_1 i_2}{2 \pi r}$Given:$i_1 = 5 	ext{ A}$$i_2 = 10 	ext{ A}$$r = 10 	ext{ cm} = 0.1 	ext{ m}$$\mu_0 = 4\pi 	imes 10^{-7} 	ext{ T m/A}$Substituting the values:$\frac{F}{\ell} = \frac{4\pi 	imes 10^{-7} 	imes 5 	imes 10}{2\pi 	imes 0.1}$$\frac{F}{\ell} = \frac{2 	imes 10^{-7} 	imes 50}{0.1} = \frac{100 	imes 10^{-7}}{0.1} = 1000 	imes 10^{-7} = 10^{-4} 	ext{ N/m}$Since the currents are in the same direction,the force between the conductors is attractive.

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