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(B) The distance between two consecutive nodes in a stationary wave is given by $\lambda/2$.Given that the velocity of the waves is $v = 16 \ m/s$ and

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$8/n$

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(B) The distance between two consecutive nodes in a stationary wave is given by $\lambda/2$.Given that the velocity of the waves is $v = 16 \ m/s$ and the frequency is $n$.The relationship between velocity,frequency,and wavelength is $v = n\lambda$,which implies $\lambda = v/n$.Substituting the value of $\lambda$ into the expression for the distance between two nodes:Distance $= \lambda/2 = (v/n)/2 = v/(2n)$.Substituting $v = 16 \ m/s$:Distance $= 16/(2n) = 8/n$.

Column - $A$	Column - $B$
$(a)$ Minimum change in pressure	$(i)$ Antinodal point
$(b)$ Maximum change in pressure	$(ii)$ Nodal point

Two waves are approaching each other with a velocity of $16 \ m/s$ and frequency $n$. The distance between two consecutive nodes is

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