Two waves having intensity I and 9I produce i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resultant intensity $I_R$ of two interfering waves with intensities $I_1$ and $I_2$ and phase difference $\phi$ is given by the formula:$I_R =

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(D) The resultant intensity $I_R$ of two interfering waves with intensities $I_1$ and $I_2$ and phase difference $\phi$ is given by the formula:$I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$Given $I_1 = I$,$I_2 = 9I$,and $I_R = 7I$,substitute these values into the equation:$7I = I + 9I + 2\sqrt{I \cdot 9I} \cos \phi$Simplify the equation:$7I = 10I + 2(3I) \cos \phi$$7I = 10I + 6I \cos \phi$Subtract $10I$ from both sides:$-3I = 6I \cos \phi$Divide by $6I$:$\cos \phi = -\frac{3I}{6I} = -\frac{1}{2}$Since $\cos \phi = -\frac{1}{2}$,the phase difference $\phi$ is $120^{\circ}$.

Two waves having intensity $I$ and $9I$ produce interference. If the resultant intensity at a point is $7I$,the phase difference between the two waves is.....$^o$

Similar Questions

$A$ uniform rope of mass $0.1 ~kg$ and length $2.45 ~m$ hangs from a rigid support. The time taken by the transverse wave formed in the rope to travel through the full length of the rope is (Assume $g=9.8 ~m/s^2$) (in $~s$)

The figure shows a system of logic gates. From the study of the truth table,it can be found that to produce a high output $(1)$ at $R$,we must have

$A$ body is projected vertically upwards with a velocity $u$ from the top of a tower. The time taken by it to reach the ground is $n$ times the time taken by it to reach the highest point in its path. The height of the tower is:

Work done in time $t$ on a body of mass $m$ which is accelerated from rest to a speed $v$ in time $t_1$ as a function of time $t$ is given by:

The two lenses of an achromatic doublet should have:

Vedclass Test Series

Exam Paper Generator

Online Exam Module