Two waves having intensity I and 9I produce i | vedclass

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(D) The resultant intensity $I_R$ of two interfering waves is given by the formula: $I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$,where $\phi$ is the

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$120$

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(D) The resultant intensity $I_R$ of two interfering waves is given by the formula: $I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$,where $\phi$ is the phase difference.Given $I_1 = I$,$I_2 = 9I$,and $I_R = 7I$.Substituting these values into the formula:$7I = I + 9I + 2\sqrt{I \cdot 9I} \cos \phi$$7I = 10I + 2(3I) \cos \phi$$7I = 10I + 6I \cos \phi$$-3I = 6I \cos \phi$$\cos \phi = -\frac{3I}{6I} = -\frac{1}{2}$Since $\cos \phi = -\frac{1}{2}$,the phase difference $\phi = 120^o$.

Two waves having intensity $I$ and $9I$ produce interference. If the resultant intensity at a point is $7I$,what is the phase difference between the two waves?........$^o$

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