Two wires of same length are bent to form a circular loop with two turns and a square loop of one turn. Both of them carry the same current. The ratio of the magnetic moment of the circular loop of two turns to that of the square loop is

$A$ wire of length $2\,m$ is bent into a circular loop. When a current of $1\,A$ is passed through the loop,then the magnetic moment of the loop is

$A$ square loop is carrying a steady current $I$ and the magnitude of its magnetic dipole moment is $m$. If this square loop is changed to a circular loop and it carries the same current,the magnitude of the magnetic dipole moment of the circular loop will be

Write the formula for the magnetic field due to a current-carrying loop acting as a magnetic dipole at a point on its axis,and compare it with the formula for the electric field of an electric dipole.

Which of the following is a valid $SI$ unit for magnetic moment?

$A$ steady current $i$ flows in a small square loop of wire of side $L$ in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let $\overrightarrow {{\mu _1}} $ and $\overrightarrow {{\mu _2}} $ respectively denote the magnetic moments due to the current loop before and after folding. Then