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(B) The efficiency of a Carnot engine is given by the formula $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the temperature of the source and $T_2$ is t

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When the temperature of the sink is $0 \ K$.

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(B) The efficiency of a Carnot engine is given by the formula $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the temperature of the source and $T_2$ is the temperature of the sink.For the efficiency $\eta$ to be $100 \%$ (or $1$),the term $\frac{T_2}{T_1}$ must be equal to $0$.This condition is satisfied if the temperature of the sink $T_2$ is $0 \ K$ (absolute zero),while the source temperature $T_1$ remains finite and greater than $0 \ K$.

Under which ideal condition does the efficiency of a Carnot engine become $100 \%$?

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