What is the degree of unsaturation (double bo | vedclass

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Question

(D) The reaction shows that compound $(A)$ reacts with $2H_2$ to form Carlina oxide. Carlina oxide has the structure $C_6H_5-CH_2-CH_2-CH_2-(C_4H_3O)$

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(D) The reaction shows that compound $(A)$ reacts with $2H_2$ to form Carlina oxide. Carlina oxide has the structure $C_6H_5-CH_2-CH_2-CH_2-(C_4H_3O)$. The molecular formula of Carlina oxide is $C_{13}H_{12}O$. The degree of unsaturation ($D$.$U$.) for $C_{13}H_{12}O$ is calculated as: $D.U. = C + 1 - \frac{H}{2} + \frac{N}{2} - \frac{X}{2} = 13 + 1 - \frac{12}{2} = 14 - 6 = 8$. Since compound $(A)$ reacts with $2H_2$ to form Carlina oxide,it means $2$ moles of $H_2$ were added to saturate two double bonds present in $(A)$. Therefore,the $D$.$U$. of compound $(A)$ is $8 + 2 = 10$.

What is the degree of unsaturation (double bond equivalent) in compound $(A)$?

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