Using the following data,draw a time-displacement graph for a moving object:

Time $(s)$	$0, 2, 4, 6, 8, 10, 12, 14, 16$
Displacement $(m)$	$0, 2, 4, 4, 4, 6, 4, 2, 0$

Use this graph to find the average velocity for the first $4 \, s$,for the next $4 \, s$,and for the last $6 \, s$.

(N/A) Average velocity is defined as the total change in displacement divided by the total time taken.
$1$. For the first $4 \, s$ ($t = 0$ to $4 \, s$):
Average velocity $v = \frac{\Delta x}{\Delta t} = \frac{4 - 0}{4 - 0} = \frac{4}{4} = 1 \, m/s$.
$2$. For the next $4 \, s$ ($t = 4$ to $8 \, s$):
Average velocity $v = \frac{\Delta x}{\Delta t} = \frac{4 - 4}{8 - 4} = \frac{0}{4} = 0 \, m/s$.
$3$. For the last $6 \, s$ ($t = 10$ to $16 \, s$):
Average velocity $v = \frac{\Delta x}{\Delta t} = \frac{0 - 6}{16 - 10} = \frac{-6}{6} = -1 \, m/s$.