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(C) The reduction of a ketone using $LiAlH_4$ follows the stoichiometry where $4$ moles of the ketone react with $1$ mole of $LiAlH_4$ to form an alum

Vedclass · Accepted Answer

$1/4$

Vedclass · Answer

(C) The reduction of a ketone using $LiAlH_4$ follows the stoichiometry where $4$ moles of the ketone react with $1$ mole of $LiAlH_4$ to form an aluminum alkoxide intermediate. The balanced reaction is: $4 	ext{ Cyclobutanone} + LiAlH_4 ightarrow (	ext{Cyclobutoxy})_4AlLi$. Upon hydrolysis with $H_3O^{\oplus}$,this yields $4$ moles of cyclobutanol. Therefore,the stoichiometric coefficient $x$ for $LiAlH_4$ relative to $4$ moles of cyclobutanone is $1/4$.

The value of $x$ in the above reaction is:

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