Values of dissociation constant,$K_a$ are given as follows:
Acid $K_a$ $HCN$ $6.2 \times 10^{-10}$ $HF$ $7.2 \times 10^{-4}$ $HNO_2$ $4.0 \times 10^{-4}$
Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be:
| Acid | $K_a$ |
| $HCN$ | $6.2 \times 10^{-10}$ |
| $HF$ | $7.2 \times 10^{-4}$ |
| $HNO_2$ | $4.0 \times 10^{-4}$ |
Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be:
- A$F^{-} < CN^{-} < NO_2^-$
- B$NO_2^- < CN^{-} < F^{-}$
- C$F^{-} < NO_2^- < CN^{-}$
- D$NO_2^- < F^{-} < CN^{-}$
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Which of the following oxides will not give $OH^{-}$ ions in aqueous solution?
Medium
View SolutionMatch the following acids in List-$I$ with their respective acid dissociation constants $(K_a)$ in List-$II$:
List-$I$ (Acid) List-$II$ $(K_a)$ $A$. Phenol $I$. $1 \times 10^{-13}$ $B$. Benzoic acid $II$. $3.0 \times 10^{-8}$ $C$. $HClO$ $III$. $1.0 \times 10^{-10}$ $D$. $CH_3COOH$ $IV$. $6.5 \times 10^{-5}$ $V$. $1.75 \times 10^{-5}$
The correct match is:
| List-$I$ (Acid) | List-$II$ $(K_a)$ |
|---|---|
| $A$. Phenol | $I$. $1 \times 10^{-13}$ |
| $B$. Benzoic acid | $II$. $3.0 \times 10^{-8}$ |
| $C$. $HClO$ | $III$. $1.0 \times 10^{-10}$ |
| $D$. $CH_3COOH$ | $IV$. $6.5 \times 10^{-5}$ |
| $V$. $1.75 \times 10^{-5}$ |
The correct match is:
The correct order of increasing basicity of the given conjugate bases $(R = CH_3)$ is
MediumAIEEE 2010
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View SolutionWhich of the following statements is true for a basic solution?
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