Values of the four quantum numbers for the la | vedclass

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(D) The quantum numbers $n = 4, l = 1$ indicate that the last electron enters the $4p$ orbital.For $l = 1$,the possible values of $m$ are $-1, 0, +1$.

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(D) The quantum numbers $n = 4, l = 1$ indicate that the last electron enters the $4p$ orbital.For $l = 1$,the possible values of $m$ are $-1, 0, +1$.The electron is in the $4p$ orbital with $m = +1$ and $s = -1/2$,which corresponds to the last electron of the $p$-block element.The electronic configuration of the atom is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6$.Summing the electrons: $2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 = 36$.Therefore,the atomic number is $36$,which corresponds to Krypton $(Kr)$.

Values of the four quantum numbers for the last electron in the atom are $n = 4, l = 1, m = +1$ and $s = -1/2$. Atomic number of the atom will be

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