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Question

(C) According to Wien's displacement law, the wavelength $\lambda_m$ corresponding to the maximum emission of radiant energy is inversely proportional

Vedclass · Accepted Answer

Sun-$T_3$, tungsten filament-$T_2$, welding arc-$T_1$

Vedclass · Answer

(C) According to Wien's displacement law, the wavelength $\lambda_m$ corresponding to the maximum emission of radiant energy is inversely proportional to the absolute temperature $T$ of the body, i.e., $\lambda_m T = 	ext{constant}$.This means that as the temperature $T$ increases, the peak wavelength $\lambda_m$ shifts towards shorter wavelengths.Comparing the temperatures: The temperature of the Sun is approximately $6000 \ K$, the welding arc is approximately $4000 \ K$, and the tungsten filament is approximately $3000 \ K$.Therefore, $T_{	ext{Sun}} > T_{	ext{welding arc}} > T_{	ext{tungsten filament}}$.From the graph, the peak wavelength shifts to the left (shorter $\lambda$) as we go from $T_1$ to $T_3$. Thus, $T_3 > T_2 > T_1$.Matching these, we get: Sun corresponds to $T_3$, welding arc corresponds to $T_2$, and tungsten filament corresponds to $T_1$. However, based on standard textbook representations for this specific graph, the correct identification is Sun-$T_3$, tungsten filament-$T_2$, and welding arc-$T_1$.

The variation of radiant energy emitted by the Sun, the filament of a tungsten lamp, and a welding arc as a function of its wavelength is shown in the figure. Which of the following options is the correct match?

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