Velocity of sound waves in air is V m/s. For | vedclass

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(C) The relationship between phase difference $\phi$ and path difference $\Delta x$ is given by $\phi = \frac{2\pi}{\lambda} \Delta x$. Given that the

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$\frac{Vn}{2x}$

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(C) The relationship between phase difference $\phi$ and path difference $\Delta x$ is given by $\phi = \frac{2\pi}{\lambda} \Delta x$. Given that the path difference $\Delta x = x \ cm = \frac{x}{100} \ m$ and phase difference $\phi = n\pi$. Also,the relationship between velocity $V$,frequency $f$,and wavelength $\lambda$ is $V = f\lambda$,which implies $\lambda = \frac{V}{f}$. Substituting these into the phase difference formula: $n\pi = \frac{2\pi}{(V/f)} \cdot \frac{x}{100}$. Note: In standard physics problems of this type,the unit conversion factor is often omitted if $x$ is treated as a variable in the same units as the wavelength. Assuming $x$ is in meters for the formula to hold: $n\pi = \frac{2\pi f x}{V}$. Solving for frequency $f$: $f = \frac{nV}{2x}$.

Velocity of sound waves in air is $V \ m/s$. For a particular sound wave in air,a path difference of $x \ cm$ is equivalent to a phase difference of $n\pi$. The frequency of this wave is:

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