The volume of 100 L of gas increases to 120 | vedclass

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Question

(A) The formula for work done by a system during expansion against a constant external pressure is $w = -P_{ext} 	imes \Delta V$. Here,$P_{ext} = 10

Vedclass · Accepted Answer

$-4842$

Vedclass · Answer

(A) The formula for work done by a system during expansion against a constant external pressure is $w = -P_{ext} 	imes \Delta V$. Here,$P_{ext} = 10 \ bar$,$V_1 = 100 \ L$,and $V_2 = 120 \ L$. Change in volume $\Delta V = V_2 - V_1 = 120 \ L - 100 \ L = 20 \ L$. Substituting the values: $w = -10 \ bar 	imes 20 \ L = -200 \ L \ bar$. Given the conversion factor $1 \ L \ bar = 24.21 \ cal$,we convert the work to calories: $w = -200 	imes 24.21 \ cal = -4842 \ cal$. The negative sign indicates that work is done by the system.

The volume of $100 \ L$ of gas increases to $120 \ L$ at a constant temperature and an external pressure of $10 \ bar$. Calculate the work done by the system. [Given: $1 \ L \ bar = 24.21 \ cal$] (in $cal$)

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