Volume of 0.1 , M H_2SO_4 required to neutral | vedclass

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Question

(A) For $H_2SO_4$,the normality $(N)$ is related to molarity $(M)$ by the formula $N = n 	imes M$,where $n$ is the basicity of the acid. For $H_2SO_4

Vedclass · Accepted Answer

$30$

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(A) For $H_2SO_4$,the normality $(N)$ is related to molarity $(M)$ by the formula $N = n 	imes M$,where $n$ is the basicity of the acid. For $H_2SO_4$,$n = 2$.Therefore,$0.1 \, M$ $H_2SO_4$ = $0.1 	imes 2 = 0.2 \, N$ $H_2SO_4$.Using the law of equivalence: $N_1V_1 = N_2V_2$.Here,$N_1 = 0.2 \, N$ $(H_2SO_4)$,$N_2 = 0.2 \, N$ $(NaOH)$,and $V_2 = 30 \, mL$.$0.2 	imes V_1 = 0.2 	imes 30$.$V_1 = 30 \, mL$.

Volume of $0.1 \, M$ $H_2SO_4$ required to neutralize $30 \, mL$ of $0.2 \, N$ $NaOH$ is......$mL$

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