(C) According to Charles's Law,at constant pressure,$V \propto T$,so $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given: $V_1 = 300 \; cm^{3}$,$T_1 = 27 + 273

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(C) According to Charles's Law,at constant pressure,$V \propto T$,so $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given: $V_1 = 300 \; cm^{3}$,$T_1 = 27 + 273 = 300 \; K$,$T_2 = 37 + 273 = 310 \; K$.Calculating $V_2$: $V_2 = V_1 \times \frac{T_2}{T_1} = 300 \; cm^{3} \times \frac{310 \; K}{300 \; K} = 310 \; cm^{3}$.The volume of air expelled is $\Delta V = V_2 - V_1 = 310 \; cm^{3} - 300 \; cm^{3} = 10 \; cm^{3}$.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

Medium

Volume of the air that will be expelled from a vessel of $300 \; cm^{3}$ when it is heated from $27 \; ^{\circ}C$ to $37 \; ^{\circ}C$ at the same pressure will be ........... $cm^{3}$

A
$310$
B
$290$
C
$10$
D
$37$

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States of Matter

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Ideal gas equation and Related gas laws

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Volume of the air that will be expelled from a vessel of $300 \; cm^{3}$ when it is heated from $27 \; ^{\circ}C$ to $37 \; ^{\circ}C$ at the same pressure will be ........... $cm^{3}$

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$n$ moles of an ideal gas at temperature $T$ (in kelvin) occupy $V \ L$ of volume, exerting a pressure of $P$ atmospheres. What is the concentration (in $mol / L$)?

The density of methane is maximum under which conditions?

If two moles of an ideal gas at $546 \ K$ occupy a volume of $44.8 \ L$,what is the pressure of the ideal gas at $546 \ K$ (in $atm$)? $(R = 0.0821 \ L \ atm \ mol^{-1} \ K^{-1})$

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