Water is flowing in a conical tube as shown in the figure. The velocity of water at area $A_2$ is $60 \,cm/s$. The values of $A_1$ and $A_2$ are $10 \,cm^2$ and $5 \,cm^2$ respectively. The pressure difference between the two cross-sections is: (in $\,N/m^2$)

Does it matter if one uses gauge instead of absolute pressures in applying Bernoulli's equation? Explain.

Water is pumped through the hose shown below, from a lower level to an upper level. Compared to the water at point $1$, the water at point $2$:

According to Bernoulli's equation $\frac{P}{\rho g} + h + \frac{v^2}{2g} = \text{constant}$,the terms $\frac{P}{\rho g}$,$h$,and $\frac{v^2}{2g}$ are generally called respectively:

Water is flowing through a horizontal tube having cross-sectional areas of its two ends as $A$ and $A'$ such that the ratio $A/A'$ is $5$. If the pressure difference of water between the two ends is $3 \times 10^5 \, N \, m^{-2}$,the velocity of water with which it enters the tube will be ......... $m \, s^{-1}$ (neglect gravity effects).

Which fundamental law forms the basis of Bernoulli's equation?