Water is flowing through two horizontal pipes | vedclass

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(C) According to the equation of continuity for an incompressible fluid,the product of the cross-sectional area and the velocity of flow remains const

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$1$

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(C) According to the equation of continuity for an incompressible fluid,the product of the cross-sectional area and the velocity of flow remains constant: $A_1 V_1 = A_2 V_2$.Here,$d_1 = 3\, cm$ (radius $r_1 = 1.5\, cm$) and $d_2 = 6\, cm$ (radius $r_2 = 3.0\, cm$).The velocity in the narrower pipe is $V_1 = 4\, m/s$.Substituting the values into the equation: $\pi (r_1)^2 V_1 = \pi (r_2)^2 V_2$.$\pi (1.5)^2 	imes 4 = \pi (3.0)^2 	imes V_2$.$2.25 	imes 4 = 9 	imes V_2$.$9 = 9 	imes V_2$.Therefore,$V_2 = 1\, m/s$.

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