Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary of radius $\frac{r}{5}$ will be:

If water rises in a capillary tube up to $3 \, cm$,what is the diameter of the capillary tube? (Surface tension of water $T = 7.2 \times 10^{-2} \, N/m$,density $\rho = 10^3 \, kg/m^3$,$g = 10 \, m/s^2$)

Mercury has an angle of contact equal to $140^{\circ}$ with soda lime glass. $A$ narrow tube of radius $1.00 \; mm$ made of this glass is dipped in a trough containing mercury. By what amount does the mercury dip down (in $mm$) in the tube relative to the liquid surface outside? Surface tension of mercury at the temperature of the experiment is $0.465 \; N m^{-1}$. Density of mercury $= 13.6 \times 10^{3} \; kg m^{-3}$.

In a capillary tube of radius $R$,a straight thin metal wire of radius $r$ $(R > r)$ is inserted symmetrically,and one end of the combination is dipped vertically in water such that the lower end of the combination is at the same level. The rise of water in the capillary tube is $[T =$ surface tension of water,$\rho =$ density of water,$g =$ gravitational acceleration$]$.

The correct curve between the height or depression $h$ of liquid in a capillary tube and its radius $r$ is

Water rises to a height of $2\, cm$ in a capillary tube. If the tube is tilted $60^{\circ}$ from the vertical,water will rise in the tube to a length of ...... $cm$.