Water rises in a capillary tube to a certain | vedclass

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Question

(D) The upward force due to surface tension $(F_s)$ is given by the product of surface tension $(T)$ and the inner circumference $(C)$ of the capillar

Vedclass · Accepted Answer

$12.5 	imes 10^{-2} \, m$

Vedclass · Answer

(D) The upward force due to surface tension $(F_s)$ is given by the product of surface tension $(T)$ and the inner circumference $(C)$ of the capillary tube.$F_s = T 	imes C$Given that the upward force is balanced by the weight of the liquid $(W = 75 	imes 10^{-4} \, N)$,$T 	imes C = 75 	imes 10^{-4} \, N$Given $T = 6 	imes 10^{-2} \, N m^{-1}$,we have:$6 	imes 10^{-2} 	imes C = 75 	imes 10^{-4}$$C = \frac{75 	imes 10^{-4}}{6 	imes 10^{-2}}$$C = 12.5 	imes 10^{-2} \, m$Thus,the inner circumference is $12.5 	imes 10^{-2} \, m$.

Water rises in a capillary tube to a certain height such that the upward force due to surface tension is balanced by $75 \times 10^{-4} \, N$ force due to the weight of the liquid. If the surface tension of water is $6 \times 10^{-2} \, N m^{-1}$,the inner circumference of the capillary must be

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