Water rises in a capillary tube up to a height of $4 \, cm$. If it is tilted to $30^{\circ}$ from the vertical,then the length of the water column in it will be

The maximum length of a water column that can stay without falling in a vertically held capillary tube of diameter $1 \ mm$ and open at both ends is (Acceleration due to gravity $= 10 \ ms^{-2}$ and surface tension of water $= 0.07 \ Nm^{-1}$) (in $cm$)

Surface tension of two liquids (having same densities), $T_1$ and $T_2$, are measured using the capillary rise method utilizing two tubes with inner radii of $r_1$ and $r_2$ where $r_1 > r_2$. The measured liquid heights in these tubes are $h_1$ and $h_2$ respectively. [Ignore the weight of the liquid above the lowest point of the meniscus]. If $T_1 = T_2$, which of the following relations is satisfied?

The water rises in the capillary to a height of $10\, cm$. If the surface tension of water is $73 \times 10^{-3}\, N/m$,density is $10^3\, kg/m^3$ and $g = 9.8\, m/s^2$,then find the radius of the capillary. (in $, cm$)

Two capillaries of the same material but of different radii are dipped in a liquid. In one of the capillaries,the liquid rises to a height of $22 \ cm$ and in the other to $66 \ cm$. The ratio of their radii is

$A$ narrow glass capillary tube of radius $1.00 \ mm$ is dipped in a trough containing mercury. The amount by which the level of mercury dips down relative to the normal level outside the tube will be approximately $..... \ mm$.
$[$Surface tension of mercury at room temperature $= 0.465 \ N/m$,density of mercury $= 13.6 \times 10^3 \ kg/m^3$,angle of contact with glass $= 135^{\circ}$,$g = 9.8 \ m/s^2]$