Water rises up to a height $h$ in a capillary tube of a certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now,the water will rise to a height of:

The correct curve between the height or depression $h$ of liquid in a capillary tube and its radius $r$ is

In a capillary rise experiment,the water level rises to a height of $5\, cm$. If the same capillary tube is placed in water such that only $3\, cm$ of the tube projects outside the water level,then

The maximum length of a water column that can stay without falling in a vertically held capillary tube of diameter $1 \ mm$ and open at both ends is (Acceleration due to gravity $= 10 \ ms^{-2}$ and surface tension of water $= 0.07 \ Nm^{-1}$) (in $cm$)

By inserting a capillary tube up to a depth $l$ in water,the water rises to a height $h$. If the lower end of the capillary is closed inside water,the capillary is taken out,and then the closed end is opened,to what height will the water remain in the tube?

Water rises up to a height $h$ in a capillary tube immersed vertically in water. When this whole arrangement is taken to a depth $d$ in a mine,the water level rises up to a height $h^{\prime}$. If $R$ is the radius of the earth,then the ratio $\frac{h}{h^{\prime}}$ is