What are X and Y respectively in the followin | vedclass

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(A) The reaction of $4$-bromotoluene with $Br_2$ in the presence of $UV$ light is a free radical substitution reaction. This reaction occurs at the be

Vedclass · Accepted Answer

$X = 	ext{4-bromobenzyl bromide}, Y = 	ext{4-bromobenzyl alcohol}$

Vedclass · Answer

(A) The reaction of $4$-bromotoluene with $Br_2$ in the presence of $UV$ light is a free radical substitution reaction. This reaction occurs at the benzylic position,not on the aromatic ring. Therefore,$X$ is $4$-bromobenzyl bromide $(Br-C_6H_4-CH_2Br)$.When $4$-bromobenzyl bromide is treated with $OH^-$,it undergoes a nucleophilic substitution reaction $(S_N2)$ where the $Br$ atom on the side chain is replaced by an $OH$ group. Therefore,$Y$ is $4$-bromobenzyl alcohol $(Br-C_6H_4-CH_2OH)$.

What are $X$ and $Y$ respectively in the following reactions?

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