What are A, B and C in the following reaction | vedclass

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(B) The reaction of arene diazonium fluoroborate $(Ar-N_2^+ BF_4^-)$ with sodium nitrite $(NaNO_2)$ in the presence of copper $(Cu)$ powder and heat i

Vedclass · Accepted Answer

$ArNO_2, N_2, NaBF_4$

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(B) The reaction of arene diazonium fluoroborate $(Ar-N_2^+ BF_4^-)$ with sodium nitrite $(NaNO_2)$ in the presence of copper $(Cu)$ powder and heat is a method to introduce a nitro group into an aromatic ring,known as the Schiemann-like reaction or a variation of the Sandmeyer-type reaction for nitro compounds.The reaction proceeds as follows:$Ar-N_2^+ BF_4^- + NaNO_2 \xrightarrow{Cu, \Delta} ArNO_2 + N_2 + NaBF_4$Here,$A = ArNO_2$,$B = N_2$,and $C = NaBF_4$.Thus,the correct option is $B$.

What are $A, B$ and $C$ in the following reaction?
$Ar-N_2^+ BF_4^- \xrightarrow{NaNO_2, \Delta, Cu} A + B + C$

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What are $A, B$ and $C$ in the following reaction?$Ar-N_2^+ BF_4^- \xrightarrow{NaNO_2, \Delta, Cu} A + B + C$