What are A & B in the following reaction?m-Br | vedclass

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(D) The starting material is $m-bromochlorobenzene$ $(m-Br-C_6H_4-Cl)$.Step $1$: Reaction with $Mg/THF$ forms a Grignard reagent. Since $Mg$ reacts fa

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None of these

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(D) The starting material is $m-bromochlorobenzene$ $(m-Br-C_6H_4-Cl)$.Step $1$: Reaction with $Mg/THF$ forms a Grignard reagent. Since $Mg$ reacts faster with $Br$ than $Cl$ due to the lower bond dissociation energy of $C-Br$,the product $A$ is $m-chlorophenylmagnesium$ bromide $(m-Cl-C_6H_4-MgBr)$.Step $2$: The Grignard reagent $A$ reacts with acetaldehyde $(CH_3CHO)$ followed by acidic workup $(aq. NH_4Cl)$ to form a secondary alcohol. The nucleophilic $m-chlorophenyl$ group attacks the carbonyl carbon of $CH_3CHO$,resulting in $m-chlorophenyl-1-ethanol$ $(m-Cl-C_6H_4-CH(OH)CH_3)$ as product $B$.Comparing this with the given options,none of the provided structures exactly match the correct chemical products $A$ and $B$.

What are $A$ $\&$ $B$ in the following reaction?
$m-Br-C_6H_4-Cl$ $\xrightarrow{Mg/THF} A$ $\xrightarrow[(ii) \ aq. NH_4Cl]{(i) \ CH_3CHO} B$

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What are $A$ $\&$ $B$ in the following reaction?$m-Br-C_6H_4-Cl$ $\xrightarrow{Mg/THF} A$ $\xrightarrow[(ii) \ aq. NH_4Cl]{(i) \ CH_3CHO} B$