What are the enthalpies of $\sigma$-bond and $\pi$-bonds in an alkene?
- A$397 \ kJ \ mol^{-1}$ and $284 \ kJ \ mol^{-1}$
- B$284 \ kJ \ mol^{-1}$ and $397 \ kJ \ mol^{-1}$
- C$450 \ kJ \ mol^{-1}$ and $300 \ kJ \ mol^{-1}$
- D$300 \ kJ \ mol^{-1}$ and $450 \ kJ \ mol^{-1}$
Explore More
Similar Questions
The product of the following reaction will be:
Consider the following sequence of reactions: $CH_3-CH=CH_2$ $\xrightarrow[700\,K]{Cl_2} A$ $\xrightarrow[420\,K, 12\,atm]{Na_2CO_3} B$ $\xrightarrow[(ii) NaOH]{(i) HOCl} C$. Compound $C$ is:
DifficultAIEEE 2012
View SolutionFor the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:
MediumNEET 2024
View SolutionAlkene $X$ $\xrightarrow[\Delta]{KMnO_4}$ (Butan$-2-$one) $+$ (Pentanoic acid). $X$ is
Difficult
View SolutionReaction $(1): CH_3-CH=CH-CH_3$ $\xrightarrow{\text{Cold } KMnO_4} (A)$ $\xrightarrow{NaIO_4} (B)$ ($2$ moles)
Reaction $(2): CH_3-CH=CH-CH_3 \xrightarrow{KMnO_4/NaIO_4} (C)$ ($2$ moles)
Product $(B)$ and $(C)$ respectively are:
Reaction $(2): CH_3-CH=CH-CH_3 \xrightarrow{KMnO_4/NaIO_4} (C)$ ($2$ moles)
Product $(B)$ and $(C)$ respectively are:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo