What happens when benzene diazonium chloride is heated with water?
(N/A) When benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$ is heated with water,it undergoes hydrolysis to form phenol $(C_6H_5OH)$,nitrogen gas $(N_2)$,and hydrochloric acid $(HCl)$.
The chemical reaction is as follows:
$C_6H_5N_2^+Cl^- + H_2O \xrightarrow{\Delta} C_6H_5OH + N_2 + HCl$
The chemical reaction is as follows:
$C_6H_5N_2^+Cl^- + H_2O \xrightarrow{\Delta} C_6H_5OH + N_2 + HCl$
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Similar Questions
In the given reaction,identify $A$:
$C_6H_5-CH(CH_3)_2 + O_2$ $\rightarrow A$ $\xrightarrow{H_2O/H^+} C_6H_5OH + CH_3COCH_3$
$C_6H_5-CH(CH_3)_2 + O_2$ $\rightarrow A$ $\xrightarrow{H_2O/H^+} C_6H_5OH + CH_3COCH_3$
Difficult
View SolutionBenzene diazonium chloride on boiling with dilute sulphuric acid gives:
Medium
View SolutionPhenol is obtained by heating an aqueous solution of:
Medium
View SolutionConsider the following sequence of reactions:
$C_6H_6 + CH_3CH=CH_2$ $\xrightarrow[heat]{H_3PO_4} A$ $\xrightarrow[2. H_3O^{+}, heat]{1. O_2, heat} B + C$
The products $(B)$ and $(C)$ are:
$C_6H_6 + CH_3CH=CH_2$ $\xrightarrow[heat]{H_3PO_4} A$ $\xrightarrow[2. H_3O^{+}, heat]{1. O_2, heat} B + C$
The products $(B)$ and $(C)$ are:
Medium
View SolutionThe products $X$ and $Z$ in the following reaction sequence are:
$\text{Benzene} + CH_3-CH=CH_2 \xrightarrow{AlCl_3/\text{ether}, \text{Heat}} X \xrightarrow[2. H_3O^+]{1. O_2/130^{\circ}C} Z$
$\text{Benzene} + CH_3-CH=CH_2 \xrightarrow{AlCl_3/\text{ether}, \text{Heat}} X \xrightarrow[2. H_3O^+]{1. O_2/130^{\circ}C} Z$
MediumKCET 2018
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