What is Z in the following sequence of reacti | vedclass

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(B) $Z$ is Propan$-2-$ol. The reaction sequence is as follows: $CH_3-CH(OH)-CH_3 (Z)$ $\xrightarrow{PCl_5} CH_3-CHCl-CH_3 (X)$ $\xrightarrow{Alc. KOH}

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$CH_3-CH(OH)-CH_3$

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(B) $Z$ is Propan$-2-$ol. The reaction sequence is as follows: $CH_3-CH(OH)-CH_3 (Z)$ $\xrightarrow{PCl_5} CH_3-CHCl-CH_3 (X)$ $\xrightarrow{Alc. KOH} CH_3-CH=CH_2 (Y)$ $\xrightarrow{dil. H_2SO_4} CH_3-CH(OH)-CH_3 (Z)$. In the case of Propan$-1-$ol (Option $A$),the reaction would yield Propan$-2-$ol as the final product due to Markovnikov addition of water to the intermediate propene,meaning $Z$ would not be regenerated.

What is $Z$ in the following sequence of reaction?
$Z$ $\xrightarrow{PCl_5} X$ $\xrightarrow{Alc. KOH} Y$ $\xrightarrow{dil. H_2SO_4} Z$

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What is $Z$ in the following sequence of reaction? $Z$ $\xrightarrow{PCl_5} X$ $\xrightarrow{Alc. KOH} Y$ $\xrightarrow{dil. H_2SO_4} Z$