What is [H^{+}] of a solution that is 0.01 M | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The solution is a buffer containing a weak acid $(HCN)$ and its salt $(NaCN)$.Using the acid dissociation constant expression: $K_a = \frac{[H^{+}

Vedclass · Accepted Answer

$3.1 	imes 10^{-10}$

Vedclass · Answer

(D) The solution is a buffer containing a weak acid $(HCN)$ and its salt $(NaCN)$.Using the acid dissociation constant expression: $K_a = \frac{[H^{+}][CN^{-}]}{[HCN]}$Given: $K_a = 6.2 	imes 10^{-10}$,$[HCN] = 0.01 \ M$,and $[CN^{-}] = 0.02 \ M$.Substituting the values: $6.2 	imes 10^{-10} = \frac{[H^{+}](0.02)}{0.01}$$[H^{+}] = \frac{6.2 	imes 10^{-10} 	imes 0.01}{0.02}$$[H^{+}] = 3.1 	imes 10^{-10} \ M$.

What is $[H^{+}]$ of a solution that is $0.01 \ M$ in $HCN$ and $0.02 \ M$ in $NaCN$ ($K_a$ for $HCN = 6.2 \times 10^{-10}$)?

Similar Questions

Which of the following mixtures in water acts as a buffer?

The ratio of volumes of $CH_3COOH$ $0.1 \ N$ to $CH_3COONa$ $0.1 \ N$ required to prepare a buffer solution of $pH$ $5.74$ is (Given, $pK_a$ of $CH_3COOH$ is $4.74$)

Out of the following,which pair of solutions is not a buffer solution?

The acidic and basic strength of buffer solutions remains constant because ...

Find the $pH$ of a solution formed by mixing equal volumes of $0.1 \text{ M}$ sodium propionate and $0.1 \text{ M}$ propionic acid. (Given: The dissociation constant of propionic acid is $K_a = 1.3 \times 10^{-5}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module