What is Z in the following sequence of reacti | vedclass

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(C) The reaction sequence is as follows:$1$. $p-chloronitrobenzene$ reacts with $NaOH$ at $443 \ K$ to form $p-nitrophenol$ $(X)$.$2$. $p-nitrophenol$

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hydroquinone

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(C) The reaction sequence is as follows:$1$. $p-chloronitrobenzene$ reacts with $NaOH$ at $443 \ K$ to form $p-nitrophenol$ $(X)$.$2$. $p-nitrophenol$ is reduced using $Sn + HCl$ to form $p-aminophenol$ $(Y)$.$3$. $p-aminophenol$ reacts with $NaNO_2 / HCl$ at $0-5^{\circ}C$ to form a diazonium salt intermediate.$4$. Hydrolysis of this diazonium salt with $H_3O^{+}$ at $10^{\circ}C$ replaces the diazonium group with an $-OH$ group,resulting in the formation of $hydroquinone$ $(Z)$.

What is $Z$ in the following sequence of reactions?
$p-chloronitrobenzene$ $\xrightarrow{NaOH, 443 \ K} X$ $\xrightarrow{(i) Sn + HCl (ii) NaNO_2 / HCl, 0-5^{\circ}C} Y$ $\xrightarrow{H_3O^{+}, 10^{\circ}C} Z$

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What is $Z$ in the following sequence of reactions?$p-chloronitrobenzene$ $\xrightarrow{NaOH, 443 \ K} X$ $\xrightarrow{(i) Sn + HCl (ii) NaNO_2 / HCl, 0-5^{\circ}C} Y$ $\xrightarrow{H_3O^{+}, 10^{\circ}C} Z$