What is the electronic arrangement of a metal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In an octahedral complex,the $d$-orbitals split into $t_{2g}$ and $e_g$ sets.When $\Delta_{0} < P$ (where $\Delta_{0}$ is the crystal field splitt

Vedclass · Accepted Answer

$t_{2g}^3 e_g^1$

Vedclass · Answer

(C) In an octahedral complex,the $d$-orbitals split into $t_{2g}$ and $e_g$ sets.When $\Delta_{0} For a $d^4$ configuration,the first three electrons occupy the lower energy $t_{2g}$ orbitals singly according to Hund's rule.The fourth electron will occupy the higher energy $e_{g}$ orbital because the energy required to pair it in the $t_{2g}$ orbital is greater than the energy required to promote it to the $e_{g}$ orbital.Therefore,the electronic arrangement is $t_{2g}^3 e_g^1$.

What is the electronic arrangement of a metal atom/ion in an octahedral complex with $d^4$ configuration,if $\Delta_{0} < P$ (pairing energy)?

Similar Questions

$CN^{-}$ ligand containing complexes are generally ...... .

Three complexes,$[CoCl(NH_3)_5]^{2+} (I)$,$[Co(NH_3)_5H_2O]^{3+} (II)$ and $[Co(NH_3)_6]^{3+} (III)$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is

The crystal field theory is successful in explaining which of the following?
$I.$ Ligands as point charges;
$II.$ Formation and structures of complexes.
$III.$ Colour;
$IV.$ Magnetic properties;
$V.$ Covalent character of metal-ligand bonding.

The values of the crystal field stabilization energies for a high spin $d^{6}$ metal ion in octahedral and tetrahedral fields,respectively,are :

Which complex shows the highest crystal field stabilisation energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module